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mysql group sum

你确定你的第二条SQL没有问题吗? select A.senderid, b.usedspace / 1024 -- 此处应该有错误,是不是sum(b.usedspace / 1024) from tab_filelist a, tab_sender b where a.deleted = 0 and a.senderid = b.userid GROUP by a.senderid; 如果这...

您的数据结构错了,您可以将varchar(19),换成decimal类型就可以了,数字最好不要按照 字符串存储

Container和eta这两个字段建索引了吗? 1000条数据的话1秒已经够慢了

如果是想同一组中的b的总和为5,则是 select * from A where a in (select a from A group by a having sum(b)=5); 如果是想找出任意个b的总和为5,那sql写不出,只能取出所有数据在程序里进行遍历或回溯

你执行不就可以了,,应该不会

SELECT a.userid, a.mai, i.hua FROM (SELECT userid, SUM(number) AS mai FROM account WHERE state=1 GROUP BY userid) AS a, (SELECT userid, SUM(total) AS hua FROM info WHERE state=1 GROUP BY userid) AS i WHERE a.userid=i.userid AND...

select sum(zong) from table where unix_timestamp(date) between unix_timestamp('2013-05-05') and unix_timestamp('2013-09-01') group by date;

mysql的执行顺序是这样的,你想想,不知道有没有什么好的方法 1、from子句组装来自不同数据源的数据;2、where子句基于指定的条件对记录行进行筛选;3、group by子句将数据划分为多个分组;4、使用聚集函数进行计算;5、使用having子句筛选分组...

你这个情况一条语句实现不了,只能分两次。 求转入之和: SELECT SUM(金额) FROM tableName WHERE 业务类型 = 0 OR 业务类型 = 2 GROUP BY 用户id;求转出之和: SELECT SUM(金额) FROM tableName WHERE 业务类型 = 1 OR 业务类型 = 3 GOUP BY 用...

select count(if(isCheck=1,1,0)), count(if(isPay=1,1,0)),count(id) from table group by group;

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