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log3(9)=2? 为什么啊

换底公式:loga(b)=logc(b)/logc(a) 左边换成以3为底 =log3(2)/log3(9)=右边

log2(9)=log2(3²)=2log2(3) ∴log2(9)×log3(2)=2log2(3)×log3(2) =2×1 =2 望采纳

log(3)9=log(3)3^2 =2log(3)3 =2x1 =2.

2^(2+log2 3)+3^(2-log3 9) =2^2*2^(log2 3)+3^2/3^(log3 9) =4*3+9/9 =12+1 =13

log3 4/log9 8 =2*log3 2/[(3/2)*log3 2] =2/(3/2) =4/3 loga^b(c^d)=d/bloga(c)

不相等的 log3^2 (9/2)=1/2 log3 (9/2) log3(9/2)^2=2 log3 (9/2)

解析 可以这么来做 log3 9^(-1) =-log3 9 =-2 希望对你有帮助 学习进步O(∩_∩)O谢谢

log2 12-log2 4=log2 (12/3)=log2 3

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