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log2 +2log2

log2(下标)6=log2(下标) (2X3) =log2(下标)2+log2(下标)3 =1+log2(下标)3 在word写好了下标 这里却显示不出,晕 ps:你应该看看书的前面,和例题。

f(8)=f(√2^6)=log(2)√2=1/2 log(√2-1)(3+2√2)=log(√2-1)(√2+1)^2 =-2 (√2+1=1/(√2-1))

log(3+2)+log(2-3) =log5+log(-1) log(-1): ????????

log2(360) =log2(4*9*2*5) =log2(4)+log2(9)+log2(2)+log2(5) =log2(2^2)+log2(3^2)+log2(2)+log2(5) =2+2log2(3)+1+log2(5) =3+2log2(3)+log2(5)

2log210+log20.04=log2100+log20.04=log2100×0.04=log24=2故答案为:2

log2(x+1)

解:log(2)3×log(3)4 =log(2)3×log(2)4/log(2)3 =log(2)4 =log(2)2² =2log(2)2 =2

求{log₂n}的前2^n项的和 解: log₂1+log₂2+log₂3+....+log₂2^n =log₂(1+2+3+..+2^n) 1+2+3+..+2^n =(1+2^n)*2^n/2 =(1+2^n)*2^(n-1) 所以, log₂(1+2+3+..+2^n) = log₂(1+2^n)+ log₂ 2^(...

真数成等比,对数成等差 所以a1*a10=32

x+2y的最小值是4 【分析】: ∵log2x+log2y=1 ∴log2(xy)=1,x>0,y>0,且 xy=2. 则x+2y≥2√x•2y =4 当且仅当x=2y 时,等号成立. 故答案为 4. 本题考查的是基本不等式 应用基本的不等式解题,注意创设一个应用基本不等式的情境及使等...

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