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log1/3(1/2)=log3(2) 对吗 为什么

=lg0.5/lg3=-0.301/0.477=-0.631

log(1/2,3)=log(10,3)/log(10,1/2)=0.4771/-0.3010=-1.5850

log1/2(2/3) =log1/2(2)-log1/2(3) =-1+lg2(3) =-1+1.585 =0.585

解: a=log1/3[2]=-log3[2]>-log3[3]=-1,且ab

log1/3 x/2=log3 (x-1) log3 2/x =log3 (x-1) 2/x=x-1 x²-x=2 x²-x-2=0 (x+1)(x-2)=0 x=-1或x=2 但真数x/2>0,x-1>0 所以 x=2

对,这两个是相等的

a=log(1/2) =log(1/2) /log(1/3) =log2 b=log(2/3) = log (2/3) /log(1/2) = (1- log2)/log2 =-1+ 1/log2 c= log (4/3) =-1+ log4 =-1+ 2log2 c- a = -1+ log2 a> c log 2 >0.5 c-b =2log2 - 1/log2 >0 => c>b ie a>c>b

把1/2放到log里面去,相减转换成相除就可以得出结果了

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