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2log2 3+2log4 3等于多少

使用对数的换底公式,logs(N)=logb(N)/logb(a). log4(3)=log2(3)/log2(4)=1/2*log2(3)=log√3 2log2 3+2log4 3=3log2 3

log2,3 知道提示关闭 您的提问(回答)过于简略,请再丰富一下内容重新提交

(log4∧3+log4∧2)log6∧2 =[log4^(3×2)]log6^2 =log4^6 log6^2 =lg2/lg4 =1/2

都换成以2为底的对数进行比较 log2(3)=log2(根号9) log4(5)=log2(根号5) 3/2=log2(2^(3/2))=log2(根号8) 因为y=log2(x)在(0,+无穷)上为增函数 所以log2(3)>3/2>log4(5)

1

log2+log3=log6 如下图所示,是“4”的第一个公式的逆运算

log2(3)-log4(6) = log2(3)-log2^2((√6)^2) = log2(3)-log2(√6) = log2(3/√6) = log2(√3/√2) = log2(√3)-log2(√2) = 1/2log2(3) - 1/2 如果题目是【log2(3)-log4(36)】 log2(3)-log4(36) = log2(3)-log2^2((6)^2) = log2(3)-log2(6) = log2(3/6)...

(log3 2+log9 2)*(log4 3+log8 3) =(lg2/lg3+lg2/lg9)*(lg3/lg4+lg3/lg8) =(lg2/lg3+lg2/2lg3)*(lg3/2lg2+lg3/3lg2 =3/2*lg2/lg3*5/6*lg3/lg2 =3/2*5/6=5/4

你没打出对数的底数,就看成是相同的底来做吧 log(3-x)^2=log[4(6-x)] (3-x)^2=4(6-x) x^2-6x+9=24-4x x^2-2x-15=0 (x-5)(x+3)=0 x=5或x=-3 又3-x>0,x0,x

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